jwt13 Posted January 16, 2010 Share Posted January 16, 2010 Ok so I have my Algebra 1 exam on tuesday and I need help to understand how to do a problem like this. 2y=3/2X - 14 I need to know how to solve for Y I,ve learned it before it seems simple and was one of the first things we learned but i cant find nothing on it in my notes or my book so if you could explain please do so Link to comment Share on other sites More sharing options...

praguepride Posted January 16, 2010 Share Posted January 16, 2010 First you solve for x then you replace the x with the y and you can then solve it Link to comment Share on other sites More sharing options...

praguepride Posted January 16, 2010 Share Posted January 16, 2010 2y=3/2X - 14 2y + 14 = 3/2x (4y + 28)/3 = x Then you go back to the original equation and replace x with 3y + 21 so 2y = 3/2((4y + 28)/3) - 14 do the math... http://www.jamesbrennan.org/algebra/systems/substitution_method.htm Link to comment Share on other sites More sharing options...

d_w_w Posted January 16, 2010 Share Posted January 16, 2010 Making it too complicated I think. Just divide both sides of the equation by 2, no? Link to comment Share on other sites More sharing options...

d_w_w Posted January 16, 2010 Share Posted January 16, 2010 2y=3/2X - 14 2y + 14 = 3/2x (4y + 28)/3 = x Then you go back to the original equation and replace x with 3y + 21 so 2y = 3/2((4y + 28)/3) - 14 do the math... If you do the math: 2y = (3/2)(4y/3) + (3/2)(28/3) - 14 2y = 2y + 14 - 14 2y = 2y y = y Can't use substitution with a single equation. Link to comment Share on other sites More sharing options...

jwt13 Posted January 16, 2010 Author Share Posted January 16, 2010 Making it too complicated I think. Just divide both sides of the equation by 2, no? Thats what I'm thinking we did but im not 100% sure. Link to comment Share on other sites More sharing options...

Craig Edwards Posted January 16, 2010 Share Posted January 16, 2010 y=3x/4-7 is the answer. It is hard to write how to do it on these broads but basicly you divide both ends by 2 so you can get that 2 off the y and then times the 2 on the 3/2 that brings it to 4 an you always put the variable on the top. I'm not that good at explaning it but that is how you do it for that one problem Link to comment Share on other sites More sharing options...

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